Is Michelle Rodriguez gay? DUI?! Fast, furious, drunk, and gay????

Michelle Rodriguez and Cynthia Watros were arrested within 15 minutes of each other on DUI charges.

Is Michelle Rodriguez a lesbian? Oh God in Heaven, I hope so! Wouldn't that just be like Christmas? I know, I know... just look at her. My gaydar is going off so loud it can be heard in outerspace. So aside of that, yes, Michelle and her LOST co-star were arrested some time last week after drinking at a club together. Rumors say they left the club in seperate cars, following one another, then were both pulled over. You know what they had to be thinking when they saw those dreaded red and blue lights in the rear view. That sucks! While Cynthia pleaded guilty and is "remorseful", Michelle has pleaded not guilty. I have no idea of where it has gone from there. I do know that she is supposedly already on probation from a "domestic" incident a while back... AKA a fight with her girlfriend where in the cops were called. I dont know the whole scoop and dont pretend to. I simply walk away from that sentence with the important information. The part that says "her girlfriend". I don't know anything about Michelle (don't you love how I consider myself on a first name basis with her like we hang out all the time or something...?) anyway, I don't know her personally, (dang it!!!) but I do know she's a great actress and seems like a very cool, laid back person in interviews. She seems like she'd be a lot of fun to hang out with, make out with.... whatever. She also comes across as a very smart, down to earth, funny girl. A regular ol' Jane, so to speak, rather than a concieted, above it all, movie star. I love LOST. Couldn't care less what SWAT is about, but will probably own it just because she is wearing that uniform. Mmmmm. And, I have a whole new view of cops ever since Anna Lucia was working that uniform on LOST. I don't know about you, but if all cops looked like that, I'd be getting pulled over daily. What can I say? I'm a sucker for assertive, tough girls.